$16m^2-4m+3=0$
$2x\:-\:7x\:-\:9x\:$
$49^2-42+9$
$4\left(x+2\right)-3\left(x-5\right)f$
$-6+\left[4-3-\left(7+6-5\right)-8\right]+9-\left(7+6\right)$
$\left(-23\right)\:\left(-25\right)\:\left(2\right)\:$
$\left(\frac{16a^0}{3b^4}\right)+1+7$
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