$\lim_{x\to\infty}\left(\frac{4x+1}{4x-2}\right)$
$6x+7=8x-17$
$1-\left(-10\right)$
$256b^2x^2-9$
$\frac{dy}{dx}=\frac{1}{p^{\text{4}}-m^4}$
$\int x^2\left(5+\frac{x^3}{2}\right)^3dx$
$\frac{1}{x-1}>1$
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