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Solve the integral of logarithmic functions $\int\ln\left(x\cos\left(y\right)\right)dx$

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ln
log
log
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Dx
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<
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sin
cos
tan
cot
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asin
acos
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sinh
cosh
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asinh
acosh
atanh
acoth
asech
acsch

23. Integral dv/v (du/u , dx/x) = logaritmo natural (ln)

https://www.youtube.com/watch?v=6qLsxmbRBD8

Calculus - Take the derivative using product rule with natural logarithms,, ln(y) = (x^2)ln(x)

https://www.youtube.com/watch?v=4TpfQj_Wj84

Finding intercepts from an equation | Algebra I | Khan Academy

https://www.youtube.com/watch?v=xGmef7lFc5w

Calculus - Using power rule with square root to take derivative on a logarithm, d(ln(sqrt(x+1)))/dx

https://www.youtube.com/watch?v=vbgVpjL8ucU

Calculus - Find the derivative of natural logarithm using product property, d(ln(2x))/dx

https://www.youtube.com/watch?v=urYZhqwUTI0

Integral de dx entre 1 + cos x , multiplicando por conjugado y aplicando identidades

https://www.youtube.com/watch?v=ZepYdR310Sk

Function Plot

Plotting: $\frac{x\cos\left(y\right)\ln\left(x\cos\left(y\right)\right)-x\cos\left(y\right)}{\cos\left(y\right)}+C_0$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Integrals involving Logarithmic Functions

They are those integrals where the function that we are integrating is composed only of combinations of logarithmic functions.

Used Formulas

1. See formulas

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