$\left(8x-7^2\right)$
$10\:cm\:b\:20cm\:\sqrt{300}$
$y=1-\cos^2x$
$\int\frac{4\sin\left(x\right)}{16\cos^2\left(x\right)-4\cos\left(x\right)}dx$
$\left(x+3\right)\left(x^2-x-2\right)=0$
$3x+x^2+5x-7+2x-3$
$3^0\cdot4^2^3$
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