$96+80-52+46+76-62$
$y'-4e^{5x-y}=0$
$\int32xe^{-4x}dx$
$14u-44=24u+16$
$-4\cdot23$
$\int\left(x^3\sqrt{x^2-36}\right)dx$
$\left(\frac{1}{6}m+\frac{2}{7}y\right)\left(\frac{1}{6}m-\frac{2}{7}y\right)$
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