$-11x+4+12$
$3\:-\:12\:\cdot\:-4\:+\:7$
$3x-8>4x-15$
$\lim_{x\to0}\left(1-\frac{1}{2}x\right)^{\frac{4}{x}}$
$6m^2-7m+1$
$9h^2+7,3h-12,9h^2+7,4-3,1h^3-5,2$
$\left(7a^2-2b^3\right)\left(7a^2-2b^3\right)$
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