$4\left(x+2\right)-3\left(x-5\right)<8x$
$\lim_{x\to0}\left(\frac{4x\cdot\ln\left(x\right)}{6+x^2}\right)$
$\frac{-24x^{20}y^{16}}{4a^2b^{10}}$
$2x^2+12x=-9$
$\int\frac{1}{x\sqrt{7}\tan\left(30\right)}dx$
$3\sin^22x-1=0$
$x^2-3x+2\leq 4x-8$
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