$3x+1>-2$
$\frac{\left(x+8\right)}{x}=\frac{63}{x-8}$
$-\infty^5$
$\left(\frac{x}{2}+\frac{y}{3}\right)^2$
$\sqrt{1962a^2b^5}$
$\left(ab^2-cd^3\right)\left(ab^2+cd^3\right)$
$5ax^2\:5a^3x$
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