$\frac{dy}{dx}=\frac{2x+7}{6cos\left(3y\right)}$
$9\left(-2\cdot\left(-1\right)\cdot0\right)\cdot\left(-3\right)$
$\left(3y^2+x\cos\:\left(xy\right)\right)y'\:+\left(3x^2+y\cos\:\left(xy\right)\right)=0$
$\left(3x\:+\:y^3\right)\left(3x\:-\:y^3\right)$
$3565-26$
$\frac{dy}{dx}=\left(x+2y-3\right)$
$\int x^3\left(x^4-17\right)^9dx$
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