$\frac{x-3}{x^2-3x}$
$\lim_{x\to\infty}\:x\cdot\left(1-cos\left(\frac{1}{x}\right)\right)$
$\left(x^4+6x^4y^2\right)dx+e^{x^5}ydy\:=\:0$
$x^2+x=x$
$\lim_{x\to6}\left(\frac{x^2+13x+42}{x+6}\right)$
$\lim_{x\to0}\left(\frac{4x^2-4}{\sqrt{x+3}-2}\right)$
$16m^2-49$
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