$\frac{x^5+12}{x^2+x+2}$
$y'=\frac{x^2+2}{\:y}$
$3x+6>2x$
$\lim_{x\to0}\left(8x^2-12x\right)$
$\left(5+1\right)\left(2\right)$
$\left(2\cdot3\right)^{-3}$
$\:\left(8x-6\right)\left(8x-6\right)$
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