$-3x<-1$
$\sqrt[3]{\frac{a^2}{b^4}}\cdot\:\sqrt[4]{\frac{b}{a}}\cdot\:\sqrt[5]{\frac{b^4}{a^3}}$
$x^2y^3+xy$
$\frac{dy}{dx}=\:4y\left(4-y\right)$
$z^2+22z+112$
$\int\frac{6x}{x^{2}-5}dx$
$y^3=x^3$
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