$\tan\left(x\right)\cdot\left(\tan\left(x\right)-2\right)=6$

$\left(x+4\right)\left(x-1\right)\left(x+3\right)\left(x+8\right)-3$

$\frac{dy}{dx}=\frac{y+\sqrt{y^2-4x^2}}{x}$

$\lim_{x\to\infty}\left(\frac{x+1}{x-2}\right)^{3x}$

$13+6x+8-5+x$

$\frac{dy}{dx}-\frac{3}{x}y=x^5e^{2x}$

$\left(m-10\right)^2$