$6^2-4^2$
$\lim_{x\to\infty}\left(1+\frac{3}{x}\right)$
$\left(x-2\right)^3\left(4^x\right)\left(\sqrt{x+1}\right)$
$\left(\left(3^23^5\right)^2\right)^0$
$\left(3x+6\right)\left(x-9\right)$
$x^3-2x^2-3x$
$a+-165=-165$
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