$10x+8=8x+16$
$\int_{-\infty}^0\left(2t^2e^t\right)dt$
$m ^ { 4 } - 17 m ^ { 2 } + 6 m$
$\frac{1-sin\left(2x\right)}{\cos\left(2x\right)}=\frac{\cos\left(2x\right)}{1+\sin\left(x\right)}$
$-x^2=-4x+4y^2$
$\lim_{x\to0}\left(\frac{e^x}{8^x}\right)$
$2\:\sin\left(teta\right)+1\:igual\:0$
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