$\sqrt{3\left(4x\right)+2^{2x}}$
$\left(x-1\right)\left(x+1\right)^3$
$-5x^2+22x-8$
$a^4+2a^2\:b^2+b^4\:$
$\frac{4-x}{1-x}=\frac{12}{3-x}$
$\lim_{x\to0}\frac{\left(\sqrt{16-x^2}-4\right)}{x}$
$\frac{a^{-6}}{a^{-8}}$
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