$\cos=\frac{12}{5}$
$\sqrt{1.1^2}$
$\left(e^3+1\right)^2e^{-2}dx+\left(e^2+1\right)^3e^{-3}dy$
$-1.5+4.5+6$
$\int\frac{sec^2x}{\sqrt{36-tan^2x}}dx$
$\frac{dy}{dx}=\frac{2e^{2x}}{y}$
$-4a^3-9$
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