$tan\left(x\:+\:y\right)\:=\:x$
$x^2dy+2ydx=xydx+x^3dy$
$2xy-6+4y$
$\frac{\sin\:^2\left(\theta\:\right)\csc\left(\theta\:\right)\sec\left(\theta\:\right)}{\tan\:\left(\theta\:\right)}$
$\frac{1}{3}y\cdot3x$
$\frac{\left(-15\right)\left(-6\right)\left(+4\right)}{\left(-15\right)\left(-12\right)}$
$-20=x-13$
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