$\left(-2x^2y\:+\:y^2=1\right)\frac{dy}{dx}$
$-7\cdot3+6$
$sin^2\theta\:\left(1+tan^2\theta\:\right)=tan^2\theta\:$
$-2x^2+30x=112$
$\left(-7x^3+6x^2-9x+9\right)+\left(4x^3+6x^2-2x-6\right)$
$\int\left(\frac{7}{x-9}\right)dx$
$8\left(x+10\right)$
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