$\frac{6x^2-4x+12}{x+4}$
$nvauyv$
$\lim_{x\to\infty}\left(\frac{5x}{5x^4-4}\right)$
$4-\left(9+2-6+5\right)-\left(-7\right)$
$\left(x-2\right)\left(x-4\right)\left(x-3\right)$
$\frac{3x-1}{\left(x+1\right)\left(x+7\right)}$
$x^2+3>\:4x$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!