$\left(2x^3\right)\cdot\left(6x^2+4x^3+5x^4+8x+3\right)$

$e^{\ln\left(y\right)}=e^{\left(\frac{-1}{x}-\ln\left(x\right)+c\right)}$

$\left(\frac{8-2}{4-2}\right)\left(\frac{2+4}{7-4}\right)$

$\lim_{n\to\infty}n\left(x^{\frac{1}{n}}-1\right)$

$\frac{d}{dx}3xy^2-2x^2y+128=0$

$x^2+16x-36=0$

$\frac{dy}{dx}=-y\cdot e^x$