$\left(\frac{1^3}{2}\right)x\left(\frac{1}{2}\right)^{-4}x\left(2\right)^4$
$3x^2-4=16x+8$
$\left(y^3+x\right)\left(z^2+w^4\right)$
$\int x^3\sqrt{2-x}dx$
$\int x\left(8x^4-\frac{1}{x^2}\right)dx$
$v^2+4v-21$
$\left(x+0.5\right)\left(x-0.3\right)$
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