$\int\frac{x^2-x-5}{\left(x^2+5\right)^2}dx$
$\int\left(\sin\left(u\right)\right)du$
$|-7|\:+\:\left(12\:+\:6\right)\:+\:|-5|\:+\:\left(-3\right)\:+\:7$
$\left(-2\right)^4:4^2$
$\left(+0.06\right)+\left(-0.01\right)$
$\frac{10x^3+23x^2+5x+6}{5x-1}$
$4x^3-17x^2-16x+5$
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