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$\int\left(6x^2+x\right)sec\left(4x^3+x^2\right)dx$

Final answer to the exercise

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Other solved exercises

$13^7.\:13^5.\:13^2$

$\int\frac{3x^4+6x^2+x+3}{x^5+2x^3+x}dx$

$\tan^2x-\frac{1}{3}=0$

$-230-10$

$3x^{-2}y^{-\frac{1}{3}}$

$1250-83-40-37$

$9\cdot9\cdot9\cdot9$
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