$\left(3x^2+1\right)^5$

$\left(x-0\right)\left(x-2.5\right)\left(x-3.75\right)$

$\sqrt[4]{16}-5\cdot\left(-12\right)-\left(-10\right)^2$

$\lim_{x\to0}\left(\frac{x-tan\left(x\right)}{x-sec\left(x\right)}\right)$

$6x^3+19x^2+9x-10$

$\int_{\infty}^4\left(4x^2\right)dx$

$\left(5m^4-11mn^2\right)^2$