$\frac{x^3+2x+1}{x^2-x+3}$
$\left(6\:\right)-\:\left(-14\right)\:-\:\left(-9\right)$
$\left(10x^2-5x-9\right)-\left(2x^2-5x+7\right)$
$1^2-3$
$\frac{dy}{dx}=\frac{x}{y+4},y\left(2\right)=0$
$x^2-x-4xy^2$
$\sqrt{6m}.\sqrt{8m}$
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