$e^{x^2}\:^{+4}\:=\:e^{5x}$
$y=x^2-\frac{16}{5}x+c$
$mx^3+mx^2-9x-m=0$
$\left(8^{-2}\right)^{-6}$
$\frac{\left(-x^3+4x\right)}{x-3}$
$\int_0^{\infty}\left(\frac{8}{\left(2x+1\right)^3}\right)dx$
$-1342+342+356+162+832$
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