$1x+2x+3x+4x+\left(5x\right)\cdot x$
$\left(\:x+2\:\right)^3$
$3\left(3x\:-\:y\right)\:-\:12\left(x\:-4y\right)$
$-\tan\left(a\right)^2\cos\left(a\right)-\cos\left(a\right)^2$
$\left(w+9\right)\left(w+6\right)$
$-144b^4+49$
$\left(3x^2b\right)^4\:$
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