$12\left(\frac{1}{6}+\frac{d}{4}\right)+5d$
$\lim_{x\to0}\left(\frac{2}{x^2\left(x+1\right)}\right)$
$9r-17=19$
$20-\frac{200}{q+20}$
$x\left(2x+5\right)$
$y'+5xe^y=0$
$\frac{\tan^2\left(u\right)}{\sec\left(u\right)-1}$
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