$\frac{dy}{dx}=y^3\:-\:3\cdot y$
$2x\:+\:3y\:-5x$
$\lim_{x\to1}\left(\frac{x^2+8x+15}{x^2-x-12}\right)$
$\int_0^{\frac{\pi}{4}}\left(\tan^5\left(\frac{x}{2}\right)\right)dx$
$\sqrt{\frac{4x^2}{3y}}$
$x^2+17x+26$
$\left(x-1\right)^0$
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