$\lim_{x\to\infty}\left(x\right)^{\frac{1}{ln\left(x\right)}}$
$t^2\:u^2\:\:t^4\:$
$x^2+2x+3=6$
$\frac{9x^2+6x+1}{3x+1}$
$\left(x^3+2x\right)^5$
$\int_{-\frac{1}{4}}^0\left(\frac{1}{\sqrt{1-4x^2}}\right)dx$
$16a^2-4a+1$
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