$\left(2a+4\right)\left(2a+4\right)$
$\lim_{x\to infinity}\left(\ln\left(1+\frac{7}{x}\right)^x\right)$
$\int x^2\cdot in\left(x\right)dx$
$\left(-5a^3b^4c^2\right)\left(-2a^2b^5\right)$
$16+24f+9f^2$
$\frac{1}{4}l\:\frac{18}{8}l$
$x\left(28+7x\right)=0$
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