$0,3+1,0$
$6^2\:x\:6$
$2b\:+\:4\:-\:3c\:+\:2b$
$k^4-6k^2-16$
$32-\infty$
$\frac{3\sqrt{x}\left(\sqrt{y}+\sqrt{x}\right)}{y-x}$
$xy=x^2+x+y$
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