$2^6\cdot2^1$
$16x^2-1=\left(4x+1\right)\left(4x-1\right)$
$\left(m-1\right)x^2-5x+2m=0$
$10\left(d-5\right)^2^a-\left(c+3\right)^3-\left(b+6\right)^5c^2;\:a=4;\:b=-7;\:c=-1;\:d=6$
$\left(x^2y-1\right)^4$
$-10z+1=-9z-8$
$\frac { 3 x ^ { 4 } - 5 x ^ { 2 } + 2 } { 3 + x ^ { 3 } }$
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