$\int\frac{\left(t+5\right)}{\left(t^2+t-2\right)}dt$
$\int\frac{x^2}{4x^3+10}dx$
$7x-41+4y-2z=0$
$6=12$
$\frac{dy}{dx}=6x^5\sqrt{y-1}$
$\frac{\tan\left(m\right)-\cot\left(m\right)}{\sin\left(m\right)-\cos\left(m\right)}$
$y'+2xy=10x$
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