$f\left(x\right)=in\left(x^3-x^2\right)$
$\left(3x-7ybz^2\right)^3$
$\lim_{x\to0}\left(\frac{\sec\left(x\right)}{x\cos\left(x\right)}\right)$
$\frac{x^4}{x^4-6x^3+4x^2}$
$4x\left(x-2\right)>\left(2x+8\right)\left(2x-8\right)$
$\int_{-a}^a\left(x\right)dx$
$5=x^2+4x+1$
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