$2a^2\cdot4a$
$\left(-10\right)\cdot12\cdot\left(-9\right)$
$\tan\left(75\right)\frac{x}{2}$
$x^2+2x+1<0$
$\left(1+tan\left(x\right)\right)\cdot\frac{sin\left(x\right)}{sin\left(x\right)+cos\left(x\right)}=\tan\left(x\right)$
$\sqrt{1008a^4b^6c^5}$
$4\:-\:6cos^2x$
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