$\lim\:_{x\to\:0}\left(\frac{\ln\:\left(\frac{2x+1}{5x+1}\right)}{x}\right)$

$\lim_{x\to-4}\left|x+4\right|$

$\lim_{x\to0}\left(\:\frac{\sin\left(6x\right)^2}{3x^2}\right)$

$3m^2+4m+1$

$\lim_{x\to1}\left(\frac{4x^2}{6x^4-5}\right)$

$\frac{7\left(\cos170^{\circ}+i\sin170^{\circ}\right)}{5\left(\cos10^{\circ}+i\sin10^{\circ}\right)}$

$27\cdot20$