$f\left(x\right)=4x+10$
$\frac{1}{l}\int_0^1\left(t^2e^{-t}\right)dt$
$\int_{\cdot\infty}^0\left(xe^{4x}\right)dx$
$\int4xe^{x^2+3}dx$
$x^2-3x>10$
$-10x+-5=-15$
$\frac{d}{dx}200-\frac{900}{x+4}-x$
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