$\left(x^2-4\right)\left(3x^2+x\right)$
$f\left(x\right)=\frac{1}{2}x+2$
$\left(x^2\right)\left(-2x^2\right)$
$40\left(a+64\right)$
$\frac{dy}{dx}=-6xy\:,\:y\left(0\right)=-4$
$\left(\sqrt[4]{16-x}\right)^1$
$4\left(2\sqrt{3}\right)$
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