$-6x\:+\:13\:=\:\left(-161\right)$
$\int_1^2\left(\frac{\sqrt{x}}{y^2}\right)dy$
$3x\left(3x^2+8x-1\right)-3\left(x^2+5\right)+2x^2\left(x-9\right)$
$x^{2}-16x+64=4$
$a-1\:=\:\sqrt{7-a}$
$\left(3x^2\right)^536x^5$
$4b+10=18$
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