$\frac{\left(\sec\left(x\right)^4-1\right)}{\left(\sec\left(x\right)^4+\sec\left(x\right)^2\right)}$
$10-\left(1-\sqrt{2}\right)$
$p=x^2y^3za$
$2>b+4$
$x^2-6=x$
$\left(\sqrt[3]{x}\left(\frac{i^3}{n^3}\right)\right)$
$\int\frac{-9x}{x^2-10x+25}dx$
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