$13\cot^2\left(x\right)-\frac{1}{\sin^2\left(x\right)}=1$

$3\sin\left(x\right)=4\sin\left(z\right)$

$\int_{\tan\left(x\right)}^{\sec\left(x\right)}\left(2x\cos\left(y\right)\right)dx$

$6-4\left(-1\right)-0+2+\left(-5\right)+9-\left(-1\right)$

$\int\left(\frac{5x^2}{\left(2x+5\right)^4}\right)dx$

$0.3\left(5\:x\:10^3\right)$

$\left(x^2-4x+7\right)\left(x-2\right)$