$\frac{a^5b^9}{a^3b}$
$\int\left(\frac{\left(4x^2\right)}{\sqrt{4-x^2}}\right)dx$
$x-15=-34$
$2cot\theta\:+2tan\theta\:=2csc\theta\:\cdot\:\:sec\theta\:$
$\frac{dy}{dx}=\frac{y+1}{x^2+1}$
$y'+5^{x+y}=0$
$\frac{10^{-1}}{10^{-5}}$
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