$\sqrt{\frac{\tan^2\left(a\right)}{1+\tan^2\left(a\right)}}=\sin\left(a\right)$
$x^3+5x^2-8x-48$
$125m^6-1000$
$43.82+53.16$
$225a^6-81b^4$
$\frac{x^3+x^2+x+1}{x-15}$
$9\cdot\frac{\left(-7\right)}{\left(-9\right)}$
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