$\left(\left(y^2+3\right)^4-1\right)^3$
$\int_{-\pi}^xsin\left(t\right)dt$
$24a-36b$
$\left(+12\right)+\:\left(-9\right)-\left(-5\right)$
$\left(6n-2\right)\left(6n+5\right)$
$2x^2-4+6x^3$
$\frac{5x}{x-3}=8+\frac{12}{x-3}$
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