$-125\cdot8$
$2^8\cdot2^2$
$-1001-\left(-10001\right)$
$6m^2\:x-15bm^2-12cm^2$
$\frac{1}{\tan}=\cot$
$\frac{6x-x^2-8}{1-\sqrt[15]{x-3}}$
$4\left(x-2\right)\le4x-8$
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