$\lim_{x\to0}\left(\frac{\frac{4}{2+x}-2}{x}\right)$
$16x^2-6y^2$
$\left(4y-3a\right)^3$
$6\cdot9\cdot\left(-1\right)$
$\left(3x^2\right)\cdot\left(27x^4-14x^3+6x^2-24x\right)$
$-.03x^2+.75x+1.5125$
$m=\left(x+4\right)\left(x-4\right)+\left(x+5\right)\left(x-5\right)-2\left(x+3\right)\left(x-3\right)$
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