$3xy^3.-3yx^2$
$9x-9-8x-32$
$4^3-6^2$
$\int\left(\left(\frac{x^2}{4}\right)-\left(-\frac{x^2}{4}-x+4\right)\right)dx$
$6x^2+\sqrt{60x}+10$
$\left(\frac{2}{3}b^8\right)^2$
$\frac{x^3+3x^2-6x-8}{x+4}=0$
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