$\int\left(\frac{6}{4-x^2}\right)dx$
$\frac{8-z}{8}-\frac{8-z}{8}$
$8x^2-4x-4=0$
$\int_{1\:}^{+\infty}\frac{1}{x^2}dx$
$2x^2+5\left(x-1\right)=x^2+9$
$\left(75\right)\left(-8\right)$
$\int_{-3}^3\sqrt{9-y^2}dy$
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